$100 Invested at 1% for 10 Years
$110.51
Future Value (compounded monthly)
$100 invested at 1% annual compound interest (compounded monthly) for 10 years will grow to $110.51. You earn $10.51 in interest. At 1%, your money doubles in approximately 72 years (Rule of 72).
Year-by-Year Growth
| Year | Balance | Interest |
|---|---|---|
| 1 | $101.00 | $1.00 |
| 2 | $102.02 | $2.02 |
| 3 | $103.04 | $3.04 |
| 4 | $104.08 | $4.08 |
| 5 | $105.12 | $5.12 |
| 6 | $106.18 | $6.18 |
| 7 | $107.25 | $7.25 |
| 8 | $108.33 | $8.33 |
| 9 | $109.41 | $9.41 |
| 10 | $110.51 | $10.51 |
Quick Reference Table
| Principal | Rate | Years | Future Value |
|---|---|---|---|
| $100 | 2% | 10 yrs | $122.12 |
| $100 | 3% | 10 yrs | $134.94 |
| $100 | 1% | 1 yrs | $101.00 |
| $100 | 1% | 2 yrs | $102.02 |
| $100 | 1% | 3 yrs | $103.04 |
| $100 | 1% | 5 yrs | $105.12 |
| $100 | 1% | 7 yrs | $107.25 |
| $100 | 1% | 15 yrs | $116.18 |
Formula Used
A = P(1 + r/n)nt
- P = $100
- r = 1% = 0.01
- n = 12 (monthly)
- t = 10 years
- A = $110.51
Frequently Asked Questions
How much will $100 grow at 1% compound interest in 10 years?
$100 grows to $110.51. Interest earned: $10.51.
How long to double $100 at 1%?
Using the Rule of 72: 72 ÷ 1 ≈ 72 years.
What is the compound interest formula?
A = P(1 + r/n)^(nt). P=$100, r=1%=0.01, n=12, t=10.